Zeph had three boxes, containing a total of 800 plastic bowls. The number of plastic bowls in Box M to the total number of plastic bowls was 3 : 8. He sold 360 plastic bowls from Box N and sold ¹₄ of the plastic bowls in Box P. The number of plastic bowls left in Box N to the number of plastic bowls left in Box P was 2 : 1. How many plastic bowls were there in Box N at first?

	Box M	Box N	Box P	Total
Before	3 u	5 u (500)		8 u (800)
		6 p + 360	4 p
Change		- 360	- 1 p
			3 p
After		2x3 = 6 p	1x3 = 3 p

8 u = 800
1 u = 800 ÷ 8 = 100

Number of plastic bowls in Box N and Box P at first
= 5 u
= 5 x 100
= 500

The number of bowls left in P is the repeated identity.
LCM of 1 and 3 = 3

6 p + 360 + 4 p = 500
6 p + 4 p = 500 - 360
10 p = 140

1 p = 140 ÷ 10 = 14

Number of bowls in Box N at first
= 6 p + 360
= 6 x 14 + 360
= 84 + 360
= 444

Answer(s):444