Oscar had three boxes, containing a total of 1430 plastic bowls. The number of plastic bowls in Box J to the total number of plastic bowls was 3 : 11. He sold 347 plastic bowls from Box K and sold ¹₃ of the plastic bowls in Box L. The number of plastic bowls left in Box K to the number of plastic bowls left in Box L was 2 : 1. How many plastic bowls were there in Box K at first?

	Box J	Box K	Box L	Total
Before	3 u	8 u (1040)		11 u (1430)
		4 p + 347	3 p
Change		- 347	- 1 p
			2 p
After		2x2 = 4 p	1x2 = 2 p

11 u = 1430
1 u = 1430 ÷ 11 = 130

Number of plastic bowls in Box K and Box L at first
= 8 u
= 8 x 130
= 1040

The number of bowls left in L is the repeated identity.
LCM of 1 and 2 = 2

4 p + 347 + 3 p = 1040
4 p + 3 p = 1040 - 347
7 p = 693

1 p = 693 ÷ 7 = 99

Number of bowls in Box K at first
= 4 p + 347
= 4 x 99 + 347
= 396 + 347
= 743

Answer(s):743