Justin had three boxes, containing a total of 1210 paper bowls. The number of paper bowls in Box T to the total number of paper bowls was 3 : 11. He sold 430 paper bowls from Box U and sold ¹₃ of the paper bowls in Box V. The number of paper bowls left in Box U to the number of paper bowls left in Box V was 3 : 1. How many paper bowls were there in Box U at first?

	Box T	Box U	Box V	Total
Before	3 u	8 u (880)		11 u (1210)
		6 p + 430	3 p
Change		- 430	- 1 p
			2 p
After		3x2 = 6 p	1x2 = 2 p

11 u = 1210
1 u = 1210 ÷ 11 = 110

Number of paper bowls in Box U and Box V at first
= 8 u
= 8 x 110
= 880

The number of bowls left in V is the repeated identity.
LCM of 1 and 2 = 2

6 p + 430 + 3 p = 880
6 p + 3 p = 880 - 430
9 p = 450

1 p = 450 ÷ 9 = 50

Number of bowls in Box U at first
= 6 p + 430
= 6 x 50 + 430
= 300 + 430
= 730

Answer(s):730