Elijah had three boxes, containing a total of 1200 styrofoam cups. The number of styrofoam cups in Box F to the total number of styrofoam cups was 3 : 8. He sold 270 styrofoam cups from Box G and sold
14 of the styrofoam cups in Box H. The number of styrofoam cups left in Box G to the number of styrofoam cups left in Box H was 2 : 1. How many styrofoam cups were there in Box G at first?
|
Box F |
Box G |
Box H |
Total |
Before |
3 u
|
5 u (750)
|
8 u (1200) |
|
|
6 p + 270 |
4 p |
|
Change |
|
- 270 |
- 1 p |
|
|
|
|
3 p |
|
After |
|
2x3 = 6 p |
1x3 = 3 p |
|
8 u = 1200
1 u = 1200 ÷ 8 = 150
Number of styrofoam cups in Box G and Box H at first
= 5 u
= 5 x 150
= 750
The number of cups left in H is the repeated identity.
LCM of 1 and 3 = 3
6 p + 270 + 4 p = 750
6 p + 4 p = 750 - 270
10 p = 480
1 p = 480 ÷ 10 = 48
Number of cups in Box G at first
= 6 p + 270
= 6 x 48 + 270
= 288 + 270
= 558
Answer(s):558