A pie cost twice as much as a wafer at a nearby restaurant. Seth spent 16 of his money on some wafers and half of the remaining sum on 5 pies. He had $35 left.
- What was the cost of 1 wafer?
- Bobby bought 2 pies and 4 wafers. How much did he spend altogether?
(a)
Fraction of Seth's amount left after buying the wafers
= 1 -
16 =
56 Fraction of Seth's amount spent on the pies
=
56 x
12 =
512 Fraction of money left
= 1 -
16 -
512 = 1 -
212 -
512 =
512 Amount that Seth had left = 5 u
5 u = 35
1 u = 35 ÷ 5 = 7
Amount that Seth had left = Amount spent on 5 pies
Cost of 5 pies = $35
Cost of 1 pie = 35 ÷ 5 = $7
Cost of 1 pie is 2 times as much as the cost of 1 wafer.
Cost of 1 wafer
= 7 ÷ 2
= $3.50
(b)
Cost of 2 pies and 4 wafers
= 2 x 7 + 4 x 3.50
= 14 + 14
= $28
Answer(s): (a) $3.50; (b) $28
