At a school carnival, each man received 5 packets of candy canes and each woman received 6 packets of candy canes. Each accompanying child received 8 packets of candy canes.
37 of the people at the school carnival were child. The ratio of the number of men to the number of women at the carnival was 5 : 8. Given that only 2416 packets of candy canes were given away, how many people were there at the carnival?
Men |
Women |
Child |
4x13 = 52 u |
3x13 = 39 u |
5x4 = 20 u |
8x4 = 32 u |
39 u |
|
Men |
Women |
Child |
Number |
20 u |
32 u |
39 u |
Value |
5 |
6 |
8 |
Total Value |
100 u |
192 u |
312 u |
Fraction of the people who were adults
= 1 -
37=
47 The number of adults is the combined repeated identity. Make the number of adults the same. LCM of 13 and 4 is 52.
Number of packets of candy canes given away
= 20 u x 5 + 32 u x 6 + 39 u x 8
= 100 u + 192 u + 312 u
= 604 u
604 u = 2416
1 u = 2416 ÷ 604 = 4
Number of people at the carnival
= 52 u + 39 u
= 91 u
= 91 x 4
= 364
Answer(s): 364