At a school carnival, each woman received 4 packets of candy canes and each man received 5 packets of candy canes. Each accompanying child received 6 packets of candy canes.
49 of the people at the school carnival were child. The ratio of the number of women to the number of men at the carnival was 3 : 7. Given that only 190 packets of candy canes were given away, how many people were there at the carnival?
Women |
Men |
Child |
5x2 = 10 u |
4x2 = 8 u |
3x1 = 3 u |
7x1 = 7 u |
8 u |
|
Women |
Men |
Child |
Number |
3 u |
7 u |
8 u |
Value |
4 |
5 |
6 |
Total Value |
12 u |
35 u |
48 u |
Fraction of the people who were adults
= 1 -
49=
59 The number of adults is the combined repeated identity. Make the number of adults the same. LCM of 10 and 5 is 10.
Number of packets of candy canes given away
= 3 u x 4 + 7 u x 5 + 8 u x 6
= 12 u + 35 u + 48 u
= 95 u
95 u = 190
1 u = 190 ÷ 95 = 2
Number of people at the carnival
= 10 u + 8 u
= 18 u
= 18 x 2
= 36
Answer(s): 36