At a school carnival, each woman received 4 packets of candy canes and each man received 6 packets of candy canes. Each accompanying child received 7 packets of candy canes.
49 of the people at the school carnival were child. The ratio of the number of women to the number of men at the carnival was 4 : 7. Given that only 1794 packets of candy canes were given away, how many people were there at the carnival?
Women |
Men |
Child |
5x11 = 55 u |
4x11 = 44 u |
4x5 = 20 u |
7x5 = 35 u |
44 u |
|
Women |
Men |
Child |
Number |
20 u |
35 u |
44 u |
Value |
4 |
6 |
7 |
Total Value |
80 u |
210 u |
308 u |
Fraction of the people who were adults
= 1 -
49=
59 The number of adults is the combined repeated identity. Make the number of adults the same. LCM of 11 and 5 is 55.
Number of packets of candy canes given away
= 20 u x 4 + 35 u x 6 + 44 u x 7
= 80 u + 210 u + 308 u
= 598 u
598 u = 1794
1 u = 1794 ÷ 598 = 3
Number of people at the carnival
= 55 u + 44 u
= 99 u
= 99 x 3
= 297
Answer(s): 297