At a school carnival, each man received 4 packets of candy canes and each woman received 5 packets of candy canes. Each accompanying child received 6 packets of candy canes.
29 of the people at the school carnival were child. The ratio of the number of men to the number of women at the carnival was 5 : 8. Given that only 4608 packets of candy canes were given away, how many people were there at the carnival?
Men |
Women |
Child |
7x13 = 91 u |
2x13 = 26 u |
5x7 = 35 u |
8x7 = 56 u |
26 u |
|
Men |
Women |
Child |
Number |
35 u |
56 u |
26 u |
Value |
4 |
5 |
6 |
Total Value |
140 u |
280 u |
156 u |
Fraction of the people who were adults
= 1 -
29=
79 The number of adults is the combined repeated identity. Make the number of adults the same. LCM of 13 and 7 is 91.
Number of packets of candy canes given away
= 35 u x 4 + 56 u x 5 + 26 u x 6
= 140 u + 280 u + 156 u
= 576 u
576 u = 4608
1 u = 4608 ÷ 576 = 8
Number of people at the carnival
= 91 u + 26 u
= 117 u
= 117 x 8
= 936
Answer(s): 936