At a school carnival, each man received 2 packets of candy canes and each woman received 4 packets of candy canes. Each accompanying child received 5 packets of candy canes.
29 of the people at the school carnival were child. The ratio of the number of men to the number of women at the carnival was 3 : 7. Given that only 2704 packets of candy canes were given away, how many people were there at the carnival?
Men |
Women |
Child |
7x10 = 70 u |
2x10 = 20 u |
3x7 = 21 u |
7x7 = 49 u |
20 u |
|
Men |
Women |
Child |
Number |
21 u |
49 u |
20 u |
Value |
2 |
4 |
5 |
Total Value |
42 u |
196 u |
100 u |
Fraction of the people who were adults
= 1 -
29=
79 The number of adults is the combined repeated identity. Make the number of adults the same. LCM of 10 and 7 is 70.
Number of packets of candy canes given away
= 21 u x 2 + 49 u x 4 + 20 u x 5
= 42 u + 196 u + 100 u
= 338 u
338 u = 2704
1 u = 2704 ÷ 338 = 8
Number of people at the carnival
= 70 u + 20 u
= 90 u
= 90 x 8
= 720
Answer(s): 720