At a school carnival, each woman received 4 packets of candy canes and each man received 6 packets of candy canes. Each accompanying child received 7 packets of candy canes.
29 of the people at the school carnival were child. The ratio of the number of women to the number of men at the carnival was 3 : 7. Given that only 1036 packets of candy canes were given away, how many people were there at the carnival?
Women |
Men |
Child |
7x10 = 70 u |
2x10 = 20 u |
3x7 = 21 u |
7x7 = 49 u |
20 u |
|
Women |
Men |
Child |
Number |
21 u |
49 u |
20 u |
Value |
4 |
6 |
7 |
Total Value |
84 u |
294 u |
140 u |
Fraction of the people who were adults
= 1 -
29=
79 The number of adults is the combined repeated identity. Make the number of adults the same. LCM of 10 and 7 is 70.
Number of packets of candy canes given away
= 21 u x 4 + 49 u x 6 + 20 u x 7
= 84 u + 294 u + 140 u
= 518 u
518 u = 1036
1 u = 1036 ÷ 518 = 2
Number of people at the carnival
= 70 u + 20 u
= 90 u
= 90 x 2
= 180
Answer(s): 180