At a school carnival, each woman received 5 packets of sweets and each man received 7 packets of sweets. Each accompanying child received 8 packets of sweets.
29 of the people at the school carnival were child. The ratio of the number of women to the number of men at the carnival was 4 : 5. Given that only 1587 packets of sweets were given away, how many people were there at the carnival?
Women |
Men |
Child |
7x9 = 63 u |
2x9 = 18 u |
4x7 = 28 u |
5x7 = 35 u |
18 u |
|
Women |
Men |
Child |
Number |
28 u |
35 u |
18 u |
Value |
5 |
7 |
8 |
Total Value |
140 u |
245 u |
144 u |
Fraction of the people who were adults
= 1 -
29=
79 The number of adults is the combined repeated identity. Make the number of adults the same. LCM of 9 and 7 is 63.
Number of packets of sweets given away
= 28 u x 5 + 35 u x 7 + 18 u x 8
= 140 u + 245 u + 144 u
= 529 u
529 u = 1587
1 u = 1587 ÷ 529 = 3
Number of people at the carnival
= 63 u + 18 u
= 81 u
= 81 x 3
= 243
Answer(s): 243