At a school carnival, each woman received 5 packets of sweets and each man received 7 packets of sweets. Each accompanying child received 8 packets of sweets.
27 of the people at the school carnival were child. The ratio of the number of women to the number of men at the carnival was 4 : 7. Given that only 5210 packets of sweets were given away, how many people were there at the carnival?
Women |
Men |
Child |
5x11 = 55 u |
2x11 = 22 u |
4x5 = 20 u |
7x5 = 35 u |
22 u |
|
Women |
Men |
Child |
Number |
20 u |
35 u |
22 u |
Value |
5 |
7 |
8 |
Total Value |
100 u |
245 u |
176 u |
Fraction of the people who were adults
= 1 -
27=
57 The number of adults is the combined repeated identity. Make the number of adults the same. LCM of 11 and 5 is 55.
Number of packets of sweets given away
= 20 u x 5 + 35 u x 7 + 22 u x 8
= 100 u + 245 u + 176 u
= 521 u
521 u = 5210
1 u = 5210 ÷ 521 = 10
Number of people at the carnival
= 55 u + 22 u
= 77 u
= 77 x 10
= 770
Answer(s): 770