A convenience store sold chicken, bacon and salmon sandwiches. The ratio of the number of chicken sandwiches made to the total number of sandwiches made was 5 : 8. The ratio of the number of bacon sandwiches made to the total number of sandwiches made was 1 : 7. After the store sold some chicken sandwiches and made another 5 bacon sandwiches, there was an equal number of chicken, bacon and salmon sandwiches left. Find the number of chicken sandwiches sold.
|
Chicken |
Bacon |
Salmon |
Total |
Comparing chicken to total |
5x7 |
|
|
8x7 |
Comparing bacon to total |
|
1x8 |
|
7x8 |
|
35 u |
8 u |
13 u |
56 u |
|
Chicken |
Bacon |
Salmon |
Total |
Before |
35 u |
8 u |
13 u |
56 u |
Change |
- 22 u |
+ 5 |
No change |
|
After |
1x13 = 13 u |
1x13 = 13 u |
1x13 = 13 u |
|
The total number of sandwiches is the same at first. Make the total number of sandwiches the same. LCM of 7 and 8 is 56.
Number of salmon sandwiches remains the same at first and in the end. Make the number of salmon sandwiches the same. LCM of 1 and 13 is 13.
Number of salmon sandwiches
= 56 u - 35 u - 8 u
= 13 u
Number of chicken, bacon and salmon sandwiches is the same in the end.
Number of bacon sandwiches = 8 u + 5
8 u + 5 = 13 u
13 u - 8 u = 5
5 u = 5
1 u = 5 ÷ 5 = 2
Number of chicken sandwiches sold
= 35 u - 13 u
= 22 u
= 22 x 2
= 44
Answer(s): 44