A convenience store sold jam, egg mayo and club sandwiches. The ratio of the number of jam sandwiches made to the total number of sandwiches made was 1 : 2. The ratio of the number of egg mayo sandwiches made to the total number of sandwiches made was 1 : 9. After the store sold some jam sandwiches and made another 21 egg mayo sandwiches, there was an equal number of jam, egg mayo and club sandwiches left. Find the number of jam sandwiches sold.
|
Jam |
Egg Mayo |
Club |
Total |
Comparing jam to total |
1x9 |
|
|
2x9 |
Comparing egg mayo to total |
|
1x2 |
|
9x2 |
|
9 u |
2 u |
7 u |
18 u |
|
Jam |
Egg Mayo |
Club |
Total |
Before |
9 u |
2 u |
7 u |
18 u |
Change |
- 2 u |
+ 21 |
No change |
|
After |
1x7 = 7 u |
1x7 = 7 u |
1x7 = 7 u |
|
The total number of sandwiches is the same at first. Make the total number of sandwiches the same. LCM of 9 and 2 is 18.
Number of club sandwiches remains the same at first and in the end. Make the number of club sandwiches the same. LCM of 1 and 7 is 7.
Number of club sandwiches
= 18 u - 9 u - 2 u
= 7 u
Number of jam, egg mayo and club sandwiches is the same in the end.
Number of egg mayo sandwiches = 2 u + 21
2 u + 21 = 7 u
7 u - 2 u = 21
5 u = 21
1 u = 21 ÷ 5 = 2
Number of jam sandwiches sold
= 9 u - 7 u
= 2 u
= 2 x 2
= 4
Answer(s): 4