A convenience store sold peanut butter, salmon and egg mayo sandwiches. The ratio of the number of peanut butter sandwiches made to the total number of sandwiches made was 3 : 7. The ratio of the number of salmon sandwiches made to the total number of sandwiches made was 1 : 5. After the store sold some peanut butter sandwiches and made another 20 salmon sandwiches, there was an equal number of peanut butter, salmon and egg mayo sandwiches left. Find the number of peanut butter sandwiches sold.
|
Peanut Butter |
Salmon |
Egg Mayo |
Total |
Comparing peanut butter to total |
3x5 |
|
|
7x5 |
Comparing salmon to total |
|
1x7 |
|
5x7 |
|
15 u |
7 u |
13 u |
35 u |
|
Peanut Butter |
Salmon |
Egg Mayo |
Total |
Before |
15 u |
7 u |
13 u |
35 u |
Change |
- 2 u |
+ 20 |
No change |
|
After |
1x13 = 13 u |
1x13 = 13 u |
1x13 = 13 u |
|
The total number of sandwiches is the same at first. Make the total number of sandwiches the same. LCM of 5 and 7 is 35.
Number of egg mayo sandwiches remains the same at first and in the end. Make the number of egg mayo sandwiches the same. LCM of 1 and 13 is 13.
Number of egg mayo sandwiches
= 35 u - 15 u - 7 u
= 13 u
Number of peanut butter, salmon and egg mayo sandwiches is the same in the end.
Number of salmon sandwiches = 7 u + 20
7 u + 20 = 13 u
13 u - 7 u = 20
6 u = 20
1 u = 20 ÷ 6 = 9
Number of peanut butter sandwiches sold
= 15 u - 13 u
= 2 u
= 2 x 9
= 18
Answer(s): 18