A convenience store sold salmon, club and ham sandwiches. The ratio of the number of salmon sandwiches made to the total number of sandwiches made was 5 : 9. The ratio of the number of club sandwiches made to the total number of sandwiches made was 1 : 8. After the store sold some salmon sandwiches and made another 18 club sandwiches, there was an equal number of salmon, club and ham sandwiches left. Find the number of salmon sandwiches sold.
|
Salmon |
Club |
Ham |
Total |
Comparing salmon to total |
5x8 |
|
|
9x8 |
Comparing club to total |
|
1x9 |
|
8x9 |
|
40 u |
9 u |
23 u |
72 u |
|
Salmon |
Club |
Ham |
Total |
Before |
40 u |
9 u |
23 u |
72 u |
Change |
- 17 u |
+ 18 |
No change |
|
After |
1x23 = 23 u |
1x23 = 23 u |
1x23 = 23 u |
|
The total number of sandwiches is the same at first. Make the total number of sandwiches the same. LCM of 8 and 9 is 72.
Number of ham sandwiches remains the same at first and in the end. Make the number of ham sandwiches the same. LCM of 1 and 23 is 23.
Number of ham sandwiches
= 72 u - 40 u - 9 u
= 23 u
Number of salmon, club and ham sandwiches is the same in the end.
Number of club sandwiches = 9 u + 18
9 u + 18 = 23 u
23 u - 9 u = 18
14 u = 18
1 u = 18 ÷ 14 = 6
Number of salmon sandwiches sold
= 40 u - 23 u
= 17 u
= 17 x 6
= 102
Answer(s): 102