A convenience store sold salmon, peanut butter and bacon sandwiches. The ratio of the number of salmon sandwiches made to the total number of sandwiches made was 5 : 8. The ratio of the number of peanut butter sandwiches made to the total number of sandwiches made was 1 : 9. After the store sold some salmon sandwiches and made another 20 peanut butter sandwiches, there was an equal number of salmon, peanut butter and bacon sandwiches left. Find the number of salmon sandwiches sold.
|
Salmon |
Peanut Butter |
Bacon |
Total |
Comparing salmon to total |
5x9 |
|
|
8x9 |
Comparing peanut butter to total |
|
1x8 |
|
9x8 |
|
45 u |
8 u |
19 u |
72 u |
|
Salmon |
Peanut Butter |
Bacon |
Total |
Before |
45 u |
8 u |
19 u |
72 u |
Change |
- 26 u |
+ 20 |
No change |
|
After |
1x19 = 19 u |
1x19 = 19 u |
1x19 = 19 u |
|
The total number of sandwiches is the same at first. Make the total number of sandwiches the same. LCM of 9 and 8 is 72.
Number of bacon sandwiches remains the same at first and in the end. Make the number of bacon sandwiches the same. LCM of 1 and 19 is 19.
Number of bacon sandwiches
= 72 u - 45 u - 8 u
= 19 u
Number of salmon, peanut butter and bacon sandwiches is the same in the end.
Number of peanut butter sandwiches = 8 u + 20
8 u + 20 = 19 u
19 u - 8 u = 20
11 u = 20
1 u = 20 ÷ 11 = 2
Number of salmon sandwiches sold
= 45 u - 19 u
= 26 u
= 26 x 2
= 52
Answer(s): 52