A convenience store sold egg mayo, ham and peanut butter sandwiches. The ratio of the number of egg mayo sandwiches made to the total number of sandwiches made was 2 : 3. The ratio of the number of ham sandwiches made to the total number of sandwiches made was 1 : 8. After the store sold some egg mayo sandwiches and made another 7 ham sandwiches, there was an equal number of egg mayo, ham and peanut butter sandwiches left. Find the number of egg mayo sandwiches sold.
|
Egg Mayo |
Ham |
Peanut Butter |
Total |
Comparing egg mayo to total |
2x8 |
|
|
3x8 |
Comparing ham to total |
|
1x3 |
|
8x3 |
|
16 u |
3 u |
5 u |
24 u |
|
Egg Mayo |
Ham |
Peanut Butter |
Total |
Before |
16 u |
3 u |
5 u |
24 u |
Change |
- 11 u |
+ 7 |
No change |
|
After |
1x5 = 5 u |
1x5 = 5 u |
1x5 = 5 u |
|
The total number of sandwiches is the same at first. Make the total number of sandwiches the same. LCM of 8 and 3 is 24.
Number of peanut butter sandwiches remains the same at first and in the end. Make the number of peanut butter sandwiches the same. LCM of 1 and 5 is 5.
Number of peanut butter sandwiches
= 24 u - 16 u - 3 u
= 5 u
Number of egg mayo, ham and peanut butter sandwiches is the same in the end.
Number of ham sandwiches = 3 u + 7
3 u + 7 = 5 u
5 u - 3 u = 7
2 u = 7
1 u = 7 ÷ 2 = 7
Number of egg mayo sandwiches sold
= 16 u - 5 u
= 11 u
= 11 x 7
= 77
Answer(s): 77