A convenience store sold jam, egg mayo and ham sandwiches. The ratio of the number of jam sandwiches made to the total number of sandwiches made was 1 : 2. The ratio of the number of egg mayo sandwiches made to the total number of sandwiches made was 1 : 7. After the store sold some jam sandwiches and made another 7 egg mayo sandwiches, there was an equal number of jam, egg mayo and ham sandwiches left. Find the number of jam sandwiches sold.
|
Jam |
Egg Mayo |
Ham |
Total |
Comparing jam to total |
1x7 |
|
|
2x7 |
Comparing egg mayo to total |
|
1x2 |
|
7x2 |
|
7 u |
2 u |
5 u |
14 u |
|
Jam |
Egg Mayo |
Ham |
Total |
Before |
7 u |
2 u |
5 u |
14 u |
Change |
- 2 u |
+ 7 |
No change |
|
After |
1x5 = 5 u |
1x5 = 5 u |
1x5 = 5 u |
|
The total number of sandwiches is the same at first. Make the total number of sandwiches the same. LCM of 7 and 2 is 14.
Number of ham sandwiches remains the same at first and in the end. Make the number of ham sandwiches the same. LCM of 1 and 5 is 5.
Number of ham sandwiches
= 14 u - 7 u - 2 u
= 5 u
Number of jam, egg mayo and ham sandwiches is the same in the end.
Number of egg mayo sandwiches = 2 u + 7
2 u + 7 = 5 u
5 u - 2 u = 7
3 u = 7
1 u = 7 ÷ 3 = 2
Number of jam sandwiches sold
= 7 u - 5 u
= 2 u
= 2 x 2
= 4
Answer(s): 4