A convenience store sold jam, bacon and tuna sandwiches. The ratio of the number of jam sandwiches made to the total number of sandwiches made was 2 : 3. The ratio of the number of bacon sandwiches made to the total number of sandwiches made was 1 : 8. After the store sold some jam sandwiches and made another 22 bacon sandwiches, there was an equal number of jam, bacon and tuna sandwiches left. Find the number of jam sandwiches sold.
|
Jam |
Bacon |
Tuna |
Total |
Comparing jam to total |
2x8 |
|
|
3x8 |
Comparing bacon to total |
|
1x3 |
|
8x3 |
|
16 u |
3 u |
5 u |
24 u |
|
Jam |
Bacon |
Tuna |
Total |
Before |
16 u |
3 u |
5 u |
24 u |
Change |
- 11 u |
+ 22 |
No change |
|
After |
1x5 = 5 u |
1x5 = 5 u |
1x5 = 5 u |
|
The total number of sandwiches is the same at first. Make the total number of sandwiches the same. LCM of 8 and 3 is 24.
Number of tuna sandwiches remains the same at first and in the end. Make the number of tuna sandwiches the same. LCM of 1 and 5 is 5.
Number of tuna sandwiches
= 24 u - 16 u - 3 u
= 5 u
Number of jam, bacon and tuna sandwiches is the same in the end.
Number of bacon sandwiches = 3 u + 22
3 u + 22 = 5 u
5 u - 3 u = 22
2 u = 22
1 u = 22 ÷ 2 = 9
Number of jam sandwiches sold
= 16 u - 5 u
= 11 u
= 11 x 9
= 99
Answer(s): 99