Will, Howard and Paul had the same number of marbles. Paul gave 0.6 of his marbles to Howard. Then Howard gave 0.15 of his marbles to Will. Finally, after Howard gave 48 marbles to Paul, he had the same number of marbles as Paul. How many marbles did Paul have at first?
| |
Will |
Howard |
Paul |
| Before |
1 u |
1 u |
1 u |
| Change 1 |
|
+ 0.6 u |
- 0.6 u |
| After 1 |
1 u |
1.6 u |
0.4 u |
| Change 2 |
+ 0.24 u |
- 0.24 u |
|
| After 2 |
1.24 u |
1.36 u |
0.4 u |
| Change 3 |
|
- 48 |
+ 48 |
| After 3 |
1.24 u |
1.36 u - 48 |
0.4 u + 48 |
Number of marbles that Howard gave to Will
= 0.15 x 1.6 u
= 0.24 u
The number of marbles that Howard and Paul had in the end is the same.
1.36 u - 48 = 0.4 u + 48
1.36 u - 0.4 u = 48 + 48
0.96 u = 96
1 u = 96 ÷ 0.96 = 100
Number of marbles that Paul had at first
= 1 u
= 100
Answer(s): 100
