Jeremy, Harry and Zane had the same number of balls. Zane gave 0.8 of his balls to Harry. Then Harry gave 0.25 of his balls to Jeremy. Finally, after Harry gave 46 balls to Zane, he had the same number of balls as Zane. How many balls did Zane have at first?
| |
Jeremy |
Harry |
Zane |
| Before |
1 u |
1 u |
1 u |
| Change 1 |
|
+ 0.8 u |
- 0.8 u |
| After 1 |
1 u |
1.8 u |
0.2 u |
| Change 2 |
+ 0.45 u |
- 0.45 u |
|
| After 2 |
1.45 u |
1.35 u |
0.2 u |
| Change 3 |
|
- 46 |
+ 46 |
| After 3 |
1.45 u |
1.35 u - 46 |
0.2 u + 46 |
Number of balls that Harry gave to Jeremy
= 0.25 x 1.8 u
= 0.45 u
The number of balls that Harry and Zane had in the end is the same.
1.35 u - 46 = 0.2 u + 46
1.35 u - 0.2 u = 46 + 46
1.15 u = 92
1 u = 92 ÷ 1.15 = 80
Number of balls that Zane had at first
= 1 u
= 80
Answer(s): 80
