Will, Tommy and Dylan had the same number of beads. Dylan gave 0.6 of his beads to Tommy. Then Tommy gave 0.35 of his beads to Will. Finally, after Tommy gave 24 beads to Dylan, he had the same number of beads as Dylan. How many beads did Dylan have at first?
| |
Will |
Tommy |
Dylan |
| Before |
1 u |
1 u |
1 u |
| Change 1 |
|
+ 0.6 u |
- 0.6 u |
| After 1 |
1 u |
1.6 u |
0.4 u |
| Change 2 |
+ 0.56 u |
- 0.56 u |
|
| After 2 |
1.56 u |
1.04 u |
0.4 u |
| Change 3 |
|
- 24 |
+ 24 |
| After 3 |
1.56 u |
1.04 u - 24 |
0.4 u + 24 |
Number of beads that Tommy gave to Will
= 0.35 x 1.6 u
= 0.56 u
The number of beads that Tommy and Dylan had in the end is the same.
1.04 u - 24 = 0.4 u + 24
1.04 u - 0.4 u = 24 + 24
0.64 u = 48
1 u = 48 ÷ 0.64 = 75
Number of beads that Dylan had at first
= 1 u
= 75
Answer(s): 75
