Ryan, Ahmad and Reggie had the same number of balls. Reggie gave 0.6 of his balls to Ahmad. Then Ahmad gave 0.25 of his balls to Ryan. Finally, after Ahmad gave 40 balls to Reggie, he had the same number of balls as Reggie. How many balls did Reggie have at first?
| |
Ryan |
Ahmad |
Reggie |
| Before |
1 u |
1 u |
1 u |
| Change 1 |
|
+ 0.6 u |
- 0.6 u |
| After 1 |
1 u |
1.6 u |
0.4 u |
| Change 2 |
+ 0.4 u |
- 0.4 u |
|
| After 2 |
1.4 u |
1.2 u |
0.4 u |
| Change 3 |
|
- 40 |
+ 40 |
| After 3 |
1.4 u |
1.2 u - 40 |
0.4 u + 40 |
Number of balls that Ahmad gave to Ryan
= 0.25 x 1.6 u
= 0.4 u
The number of balls that Ahmad and Reggie had in the end is the same.
1.2 u - 40 = 0.4 u + 40
1.2 u - 0.4 u = 40 + 40
0.8 u = 80
1 u = 80 ÷ 0.8 = 100
Number of balls that Reggie had at first
= 1 u
= 100
Answer(s): 100
