Gabriel, Will and Mark had the same number of balls. Mark gave 0.6 of his balls to Will. Then Will gave 0.15 of his balls to Gabriel. Finally, after Will gave 48 balls to Mark, he had the same number of balls as Mark. How many balls did Mark have at first?
| |
Gabriel |
Will |
Mark |
| Before |
1 u |
1 u |
1 u |
| Change 1 |
|
+ 0.6 u |
- 0.6 u |
| After 1 |
1 u |
1.6 u |
0.4 u |
| Change 2 |
+ 0.24 u |
- 0.24 u |
|
| After 2 |
1.24 u |
1.36 u |
0.4 u |
| Change 3 |
|
- 48 |
+ 48 |
| After 3 |
1.24 u |
1.36 u - 48 |
0.4 u + 48 |
Number of balls that Will gave to Gabriel
= 0.15 x 1.6 u
= 0.24 u
The number of balls that Will and Mark had in the end is the same.
1.36 u - 48 = 0.4 u + 48
1.36 u - 0.4 u = 48 + 48
0.96 u = 96
1 u = 96 ÷ 0.96 = 100
Number of balls that Mark had at first
= 1 u
= 100
Answer(s): 100
