Luis, Eric and Caden had the same number of beads. Caden gave 0.6 of his beads to Eric. Then Eric gave 0.25 of his beads to Luis. Finally, after Eric gave 22 beads to Caden, he had the same number of beads as Caden. How many beads did Caden have at first?
| |
Luis |
Eric |
Caden |
| Before |
1 u |
1 u |
1 u |
| Change 1 |
|
+ 0.6 u |
- 0.6 u |
| After 1 |
1 u |
1.6 u |
0.4 u |
| Change 2 |
+ 0.4 u |
- 0.4 u |
|
| After 2 |
1.4 u |
1.2 u |
0.4 u |
| Change 3 |
|
- 22 |
+ 22 |
| After 3 |
1.4 u |
1.2 u - 22 |
0.4 u + 22 |
Number of beads that Eric gave to Luis
= 0.25 x 1.6 u
= 0.4 u
The number of beads that Eric and Caden had in the end is the same.
1.2 u - 22 = 0.4 u + 22
1.2 u - 0.4 u = 22 + 22
0.8 u = 44
1 u = 44 ÷ 0.8 = 55
Number of beads that Caden had at first
= 1 u
= 55
Answer(s): 55
