Seth, Xavier and Caden had the same number of beads. Caden gave 0.6 of his beads to Xavier. Then Xavier gave 0.15 of his beads to Seth. Finally, after Xavier gave 24 beads to Caden, he had the same number of beads as Caden. How many beads did Caden have at first?
| |
Seth |
Xavier |
Caden |
| Before |
1 u |
1 u |
1 u |
| Change 1 |
|
+ 0.6 u |
- 0.6 u |
| After 1 |
1 u |
1.6 u |
0.4 u |
| Change 2 |
+ 0.24 u |
- 0.24 u |
|
| After 2 |
1.24 u |
1.36 u |
0.4 u |
| Change 3 |
|
- 24 |
+ 24 |
| After 3 |
1.24 u |
1.36 u - 24 |
0.4 u + 24 |
Number of beads that Xavier gave to Seth
= 0.15 x 1.6 u
= 0.24 u
The number of beads that Xavier and Caden had in the end is the same.
1.36 u - 24 = 0.4 u + 24
1.36 u - 0.4 u = 24 + 24
0.96 u = 48
1 u = 48 ÷ 0.96 = 50
Number of beads that Caden had at first
= 1 u
= 50
Answer(s): 50
