Dylan, Ken and Wesley had the same number of beads. Wesley gave 0.6 of his beads to Ken. Then Ken gave 0.25 of his beads to Dylan. Finally, after Ken gave 26 beads to Wesley, he had the same number of beads as Wesley. How many beads did Wesley have at first?
| |
Dylan |
Ken |
Wesley |
| Before |
1 u |
1 u |
1 u |
| Change 1 |
|
+ 0.6 u |
- 0.6 u |
| After 1 |
1 u |
1.6 u |
0.4 u |
| Change 2 |
+ 0.4 u |
- 0.4 u |
|
| After 2 |
1.4 u |
1.2 u |
0.4 u |
| Change 3 |
|
- 26 |
+ 26 |
| After 3 |
1.4 u |
1.2 u - 26 |
0.4 u + 26 |
Number of beads that Ken gave to Dylan
= 0.25 x 1.6 u
= 0.4 u
The number of beads that Ken and Wesley had in the end is the same.
1.2 u - 26 = 0.4 u + 26
1.2 u - 0.4 u = 26 + 26
0.8 u = 52
1 u = 52 ÷ 0.8 = 65
Number of beads that Wesley had at first
= 1 u
= 65
Answer(s): 65
