Michael, Warren and Reggie had the same number of beads. Reggie gave 0.8 of his beads to Warren. Then Warren gave 0.25 of his beads to Michael. Finally, after Warren gave 46 beads to Reggie, he had the same number of beads as Reggie. How many beads did Reggie have at first?
| |
Michael |
Warren |
Reggie |
| Before |
1 u |
1 u |
1 u |
| Change 1 |
|
+ 0.8 u |
- 0.8 u |
| After 1 |
1 u |
1.8 u |
0.2 u |
| Change 2 |
+ 0.45 u |
- 0.45 u |
|
| After 2 |
1.45 u |
1.35 u |
0.2 u |
| Change 3 |
|
- 46 |
+ 46 |
| After 3 |
1.45 u |
1.35 u - 46 |
0.2 u + 46 |
Number of beads that Warren gave to Michael
= 0.25 x 1.8 u
= 0.45 u
The number of beads that Warren and Reggie had in the end is the same.
1.35 u - 46 = 0.2 u + 46
1.35 u - 0.2 u = 46 + 46
1.15 u = 92
1 u = 92 ÷ 1.15 = 80
Number of beads that Reggie had at first
= 1 u
= 80
Answer(s): 80
