Simon, Tom and Zane had the same number of beads. Zane gave 0.6 of his beads to Tom. Then Tom gave 0.25 of his beads to Simon. Finally, after Tom gave 32 beads to Zane, he had the same number of beads as Zane. How many beads did Zane have at first?
| |
Simon |
Tom |
Zane |
| Before |
1 u |
1 u |
1 u |
| Change 1 |
|
+ 0.6 u |
- 0.6 u |
| After 1 |
1 u |
1.6 u |
0.4 u |
| Change 2 |
+ 0.4 u |
- 0.4 u |
|
| After 2 |
1.4 u |
1.2 u |
0.4 u |
| Change 3 |
|
- 32 |
+ 32 |
| After 3 |
1.4 u |
1.2 u - 32 |
0.4 u + 32 |
Number of beads that Tom gave to Simon
= 0.25 x 1.6 u
= 0.4 u
The number of beads that Tom and Zane had in the end is the same.
1.2 u - 32 = 0.4 u + 32
1.2 u - 0.4 u = 32 + 32
0.8 u = 64
1 u = 64 ÷ 0.8 = 80
Number of beads that Zane had at first
= 1 u
= 80
Answer(s): 80
