Brandon, Paul and Dylan had the same number of marbles. Dylan gave 0.6 of his marbles to Paul. Then Paul gave 0.35 of his marbles to Brandon. Finally, after Paul gave 32 marbles to Dylan, he had the same number of marbles as Dylan. How many marbles did Dylan have at first?
| |
Brandon |
Paul |
Dylan |
| Before |
1 u |
1 u |
1 u |
| Change 1 |
|
+ 0.6 u |
- 0.6 u |
| After 1 |
1 u |
1.6 u |
0.4 u |
| Change 2 |
+ 0.56 u |
- 0.56 u |
|
| After 2 |
1.56 u |
1.04 u |
0.4 u |
| Change 3 |
|
- 32 |
+ 32 |
| After 3 |
1.56 u |
1.04 u - 32 |
0.4 u + 32 |
Number of marbles that Paul gave to Brandon
= 0.35 x 1.6 u
= 0.56 u
The number of marbles that Paul and Dylan had in the end is the same.
1.04 u - 32 = 0.4 u + 32
1.04 u - 0.4 u = 32 + 32
0.64 u = 64
1 u = 64 ÷ 0.64 = 100
Number of marbles that Dylan had at first
= 1 u
= 100
Answer(s): 100
