Owen, Fred and Luis had the same number of beads. Luis gave 0.6 of his beads to Fred. Then Fred gave 0.15 of his beads to Owen. Finally, after Fred gave 24 beads to Luis, he had the same number of beads as Luis. How many beads did Luis have at first?
| |
Owen |
Fred |
Luis |
| Before |
1 u |
1 u |
1 u |
| Change 1 |
|
+ 0.6 u |
- 0.6 u |
| After 1 |
1 u |
1.6 u |
0.4 u |
| Change 2 |
+ 0.24 u |
- 0.24 u |
|
| After 2 |
1.24 u |
1.36 u |
0.4 u |
| Change 3 |
|
- 24 |
+ 24 |
| After 3 |
1.24 u |
1.36 u - 24 |
0.4 u + 24 |
Number of beads that Fred gave to Owen
= 0.15 x 1.6 u
= 0.24 u
The number of beads that Fred and Luis had in the end is the same.
1.36 u - 24 = 0.4 u + 24
1.36 u - 0.4 u = 24 + 24
0.96 u = 48
1 u = 48 ÷ 0.96 = 50
Number of beads that Luis had at first
= 1 u
= 50
Answer(s): 50
