Tommy, Albert and Billy had the same number of beads. Billy gave 0.6 of his beads to Albert. Then Albert gave 0.15 of his beads to Tommy. Finally, after Albert gave 48 beads to Billy, he had the same number of beads as Billy. How many beads did Billy have at first?
| |
Tommy |
Albert |
Billy |
| Before |
1 u |
1 u |
1 u |
| Change 1 |
|
+ 0.6 u |
- 0.6 u |
| After 1 |
1 u |
1.6 u |
0.4 u |
| Change 2 |
+ 0.24 u |
- 0.24 u |
|
| After 2 |
1.24 u |
1.36 u |
0.4 u |
| Change 3 |
|
- 48 |
+ 48 |
| After 3 |
1.24 u |
1.36 u - 48 |
0.4 u + 48 |
Number of beads that Albert gave to Tommy
= 0.15 x 1.6 u
= 0.24 u
The number of beads that Albert and Billy had in the end is the same.
1.36 u - 48 = 0.4 u + 48
1.36 u - 0.4 u = 48 + 48
0.96 u = 96
1 u = 96 ÷ 0.96 = 100
Number of beads that Billy had at first
= 1 u
= 100
Answer(s): 100
