Daniel, Perry and Archie had the same number of beads. Archie gave 0.6 of his beads to Perry. Then Perry gave 0.25 of his beads to Daniel. Finally, after Perry gave 40 beads to Archie, he had the same number of beads as Archie. How many beads did Archie have at first?
| |
Daniel |
Perry |
Archie |
| Before |
1 u |
1 u |
1 u |
| Change 1 |
|
+ 0.6 u |
- 0.6 u |
| After 1 |
1 u |
1.6 u |
0.4 u |
| Change 2 |
+ 0.4 u |
- 0.4 u |
|
| After 2 |
1.4 u |
1.2 u |
0.4 u |
| Change 3 |
|
- 40 |
+ 40 |
| After 3 |
1.4 u |
1.2 u - 40 |
0.4 u + 40 |
Number of beads that Perry gave to Daniel
= 0.25 x 1.6 u
= 0.4 u
The number of beads that Perry and Archie had in the end is the same.
1.2 u - 40 = 0.4 u + 40
1.2 u - 0.4 u = 40 + 40
0.8 u = 80
1 u = 80 ÷ 0.8 = 100
Number of beads that Archie had at first
= 1 u
= 100
Answer(s): 100
