George, Warren and Vaidev had the same number of beads. Vaidev gave 0.6 of his beads to Warren. Then Warren gave 0.25 of his beads to George. Finally, after Warren gave 28 beads to Vaidev, he had the same number of beads as Vaidev. How many beads did Vaidev have at first?
| |
George |
Warren |
Vaidev |
| Before |
1 u |
1 u |
1 u |
| Change 1 |
|
+ 0.6 u |
- 0.6 u |
| After 1 |
1 u |
1.6 u |
0.4 u |
| Change 2 |
+ 0.4 u |
- 0.4 u |
|
| After 2 |
1.4 u |
1.2 u |
0.4 u |
| Change 3 |
|
- 28 |
+ 28 |
| After 3 |
1.4 u |
1.2 u - 28 |
0.4 u + 28 |
Number of beads that Warren gave to George
= 0.25 x 1.6 u
= 0.4 u
The number of beads that Warren and Vaidev had in the end is the same.
1.2 u - 28 = 0.4 u + 28
1.2 u - 0.4 u = 28 + 28
0.8 u = 56
1 u = 56 ÷ 0.8 = 70
Number of beads that Vaidev had at first
= 1 u
= 70
Answer(s): 70
