Reggie, Paul and Vincent had the same number of beads. Vincent gave 0.6 of his beads to Paul. Then Paul gave 0.25 of his beads to Reggie. Finally, after Paul gave 28 beads to Vincent, he had the same number of beads as Vincent. How many beads did Vincent have at first?
| |
Reggie |
Paul |
Vincent |
| Before |
1 u |
1 u |
1 u |
| Change 1 |
|
+ 0.6 u |
- 0.6 u |
| After 1 |
1 u |
1.6 u |
0.4 u |
| Change 2 |
+ 0.4 u |
- 0.4 u |
|
| After 2 |
1.4 u |
1.2 u |
0.4 u |
| Change 3 |
|
- 28 |
+ 28 |
| After 3 |
1.4 u |
1.2 u - 28 |
0.4 u + 28 |
Number of beads that Paul gave to Reggie
= 0.25 x 1.6 u
= 0.4 u
The number of beads that Paul and Vincent had in the end is the same.
1.2 u - 28 = 0.4 u + 28
1.2 u - 0.4 u = 28 + 28
0.8 u = 56
1 u = 56 ÷ 0.8 = 70
Number of beads that Vincent had at first
= 1 u
= 70
Answer(s): 70
