Noah bought 25% more erasers than Maya. Luke bought 20% fewer erasers than Noah. Noah and Maya gave Luke some erasers in the ratio 3 : 2. As a result, Luke had twice as much erasers as before. Given that Maya had 18 more erasers than Noah in the end, how much erasers did Luke receive?
|
Noah
|
Maya
|
Luke
|
|
5x5
|
4x5
|
|
|
5x5
|
|
4x5
|
Before
|
25 u
|
20 u
|
20 u
|
Change |
|
|
+ (2 x 20 u) = + 40 u |
|
- 3x8 = - 24 u |
- 2x8 = - 16 u |
+ 5x8 = + 40 u |
After |
1 u |
4 u |
60 u |
100% + 25% = 125%
125% =
125100 =
54 100% - 20% = 80%
80% =
80100 =
45 The number of erasers that Noah had at first is the repeated identity.
LCM of 5 and 5 = 25
The change in the number of erasers that Luke had is the repeated identity when Noah and Maya gave to Luke.
LCM of 40 and 5 = 40
Number of erasers that Maya had more than Noah in the end
= 4 u - 1 u
= 3 u
3 u = 18
1 u = 18 ÷ 3 = 6
Number of erasers that Luke received
= 24 u + 16 u
= 40 u
= 40 x 6
= 240
Answer(s): 240