Sofia bought 50% more coins than Avery. Isabella bought 35% fewer coins than Sofia. Sofia and Avery gave Isabella some coins in the ratio 2 : 1. As a result, Isabella had twice as much coins as before. Given that Sofia had 24 less coins than Avery in the end, how much coins did Sofia and Avery give to Isabella?
|
Sofia
|
Avery
|
Isabella
|
|
3x20
|
2x20
|
|
|
20x3
|
|
13x3
|
Before
|
60 u
|
40 u
|
39 u
|
Change |
|
|
+ (2 x 39 u) = + 78 u |
|
- 2x26 = - 52 u |
- 1x26 = - 26 u |
+ 3x26 = + 78 u |
After |
8 u |
14 u |
117 u |
100% + 50% = 150%
150% =
150100 =
32 100% - 35% = 65%
65% =
65100 =
1320 The number of coins that Sofia had at first is the repeated identity.
LCM of 3 and 20 = 60
The change in the number of coins that Isabella had is the repeated identity when Sofia and Avery gave to Isabella.
LCM of 78 and 3 = 78
Number of coins that Sofia had less than Avery in the end
= 14 u - 8 u
= 6 u
6 u = 24
1 u = 24 ÷ 6 = 4
Number of coins that Sofia and Avery gave to Isabella
= 52 u + 26 u
= 78 u
= 78 x 4
= 312
Answer(s): 312