Eric had 75% fewer sweets than Xavier. After Xavier gave 295 sweets to Eric, Eric had
23 as many sweets as Xavier. How many sweets did each of them have in the end?
- Xavier
- Eric
| |
Eric |
Xavier |
Total |
| Before |
1x5 =
5 u |
4x5 =
20 u |
5x5 =
25 u |
| Change |
+ 295 |
- 295 |
|
| After |
2x5 =
10 u |
3x5 =
15 u |
5x5 =
25 u |
Number of sweets that Eric had at first in percentage
= 100% - 75%
= 25%
25% =
25100 =
14 The total number of sweets at first and in the end remains unchanged. Make the total number of sweets the same. LCM of 5 and 5 is 25.
Number of sweets that Xavier gave to Eric
= 20 u - 15 u
= 5 u
5 u = 295
1 u = 295 ÷ 5 = 59
Number of sweets that Eric had in the end
= 10 u
= 10 x 59
= 590
Number of sweets that Xavier had in the end
= 15 u
= 15 x 59
= 885
Answer(s): (a) 590; (b) 885
