Henry had 70% fewer mochi balls than Bobby. After Bobby gave 176 mochi balls to Henry, Henry had ²₃ as many mochi balls as Bobby. How many mochi balls did each of them have in the end?

1. Bobby
2. Henry

	Henry	Bobby	Total
Before	3x5 = 15 u	10x5 = 50 u	13x5 = 65 u
Change	+ 176	- 176
After	2x13 = 26 u	3x13 =  39 u	5x13 = 65 u

Number of mochi balls that Henry had at first in percentage
= 100% - 70%
= 30%

30% = ³⁰₁₀₀ = ³₁₀

The total number of mochi balls at first and in the end remains unchanged. Make the total number of mochi balls the same. LCM of 5 and 13 is 65.

Number of mochi balls that Bobby gave to Henry
= 50 u - 39 u
= 11 u

11 u = 176

1 u = 176 ÷ 11 = 16

Number of mochi balls that Henry had in the end
= 26 u
= 26 x 16
= 416

Number of mochi balls that Bobby had in the end
= 39 u
= 39 x 16
= 624

Answer(s): (a) 416; (b) 624