Paul had 60% fewer caramel apples than Elijah. After Elijah gave 260 caramel apples to Paul, Paul had ⁴₅ as many caramel apples as Elijah. How many caramel apples did each of them have in the end?

1. Elijah
2. Paul

	Paul	Elijah	Total
Before	2x9 = 18 u	5x9 = 45 u	7x9 = 63 u
Change	+ 260	- 260
After	4x7 = 28 u	5x7 =  35 u	9x7 = 63 u

Number of caramel apples that Paul had at first in percentage
= 100% - 60%
= 40%

40% = ⁴⁰₁₀₀ = ²₅

The total number of caramel apples at first and in the end remains unchanged. Make the total number of caramel apples the same. LCM of 9 and 7 is 63.

Number of caramel apples that Elijah gave to Paul
= 45 u - 35 u
= 10 u

10 u = 260

1 u = 260 ÷ 10 = 26

Number of caramel apples that Paul had in the end
= 28 u
= 28 x 26
= 728

Number of caramel apples that Elijah had in the end
= 35 u
= 35 x 26
= 910

Answer(s): (a) 728; (b) 910