Cole had 60% fewer caramel apples than Simon. After Simon gave 172 caramel apples to Cole, Cole had ²₃ as many caramel apples as Simon. How many caramel apples did each of them have in the end?

1. Simon
2. Cole

	Cole	Simon	Total
Before	2x5 = 10 u	5x5 = 25 u	7x5 = 35 u
Change	+ 172	- 172
After	2x7 = 14 u	3x7 =  21 u	5x7 = 35 u

Number of caramel apples that Cole had at first in percentage
= 100% - 60%
= 40%

40% = ⁴⁰₁₀₀ = ²₅

The total number of caramel apples at first and in the end remains unchanged. Make the total number of caramel apples the same. LCM of 5 and 7 is 35.

Number of caramel apples that Simon gave to Cole
= 25 u - 21 u
= 4 u

4 u = 172

1 u = 172 ÷ 4 = 43

Number of caramel apples that Cole had in the end
= 14 u
= 14 x 43
= 602

Number of caramel apples that Simon had in the end
= 21 u
= 21 x 43
= 903

Answer(s): (a) 602; (b) 903