Elijah had 60% fewer mochi balls than Simon. After Simon gave 360 mochi balls to Elijah, Elijah had ⁴₅ as many mochi balls as Simon. How many mochi balls did each of them have in the end?

1. Simon
2. Elijah

	Elijah	Simon	Total
Before	2x9 = 18 u	5x9 = 45 u	7x9 = 63 u
Change	+ 360	- 360
After	4x7 = 28 u	5x7 =  35 u	9x7 = 63 u

Number of mochi balls that Elijah had at first in percentage
= 100% - 60%
= 40%

40% = ⁴⁰₁₀₀ = ²₅

The total number of mochi balls at first and in the end remains unchanged. Make the total number of mochi balls the same. LCM of 9 and 7 is 63.

Number of mochi balls that Simon gave to Elijah
= 45 u - 35 u
= 10 u

10 u = 360

1 u = 360 ÷ 10 = 36

Number of mochi balls that Elijah had in the end
= 28 u
= 28 x 36
= 1008

Number of mochi balls that Simon had in the end
= 35 u
= 35 x 36
= 1260

Answer(s): (a) 1008; (b) 1260