Eric had 80% fewer candy canes than Zane. After Zane gave 357 candy canes to Eric, Eric had ²₃ as many candy canes as Zane. How many candy canes did each of them have in the end?

1. Zane
2. Eric

	Eric	Zane	Total
Before	1x5 = 5 u	5x5 = 25 u	6x5 = 30 u
Change	+ 357	- 357
After	2x6 = 12 u	3x6 =  18 u	5x6 = 30 u

Number of candy canes that Eric had at first in percentage
= 100% - 80%
= 20%

20% = ²⁰₁₀₀ = ¹₅

The total number of candy canes at first and in the end remains unchanged. Make the total number of candy canes the same. LCM of 5 and 6 is 30.

Number of candy canes that Zane gave to Eric
= 25 u - 18 u
= 7 u

7 u = 357

1 u = 357 ÷ 7 = 51

Number of candy canes that Eric had in the end
= 12 u
= 12 x 51
= 612

Number of candy canes that Zane had in the end
= 18 u
= 18 x 51
= 918

Answer(s): (a) 612; (b) 918