Daniel had 80% fewer candy canes than Ben. After Ben gave 396 candy canes to Daniel, Daniel had ³₄ as many candy canes as Ben. How many candy canes did each of them have in the end?

1. Ben
2. Daniel

	Daniel	Ben	Total
Before	1x7 = 7 u	5x7 = 35 u	6x7 = 42 u
Change	+ 396	- 396
After	3x6 = 18 u	4x6 =  24 u	7x6 = 42 u

Number of candy canes that Daniel had at first in percentage
= 100% - 80%
= 20%

20% = ²⁰₁₀₀ = ¹₅

The total number of candy canes at first and in the end remains unchanged. Make the total number of candy canes the same. LCM of 7 and 6 is 42.

Number of candy canes that Ben gave to Daniel
= 35 u - 24 u
= 11 u

11 u = 396

1 u = 396 ÷ 11 = 36

Number of candy canes that Daniel had in the end
= 18 u
= 18 x 36
= 648

Number of candy canes that Ben had in the end
= 24 u
= 24 x 36
= 864

Answer(s): (a) 648; (b) 864