Fabian had 60% fewer candy canes than Sean. After Sean gave 248 candy canes to Fabian, Fabian had ²₃ as many candy canes as Sean. How many candy canes did each of them have in the end?

1. Sean
2. Fabian

	Fabian	Sean	Total
Before	2x5 = 10 u	5x5 = 25 u	7x5 = 35 u
Change	+ 248	- 248
After	2x7 = 14 u	3x7 =  21 u	5x7 = 35 u

Number of candy canes that Fabian had at first in percentage
= 100% - 60%
= 40%

40% = ⁴⁰₁₀₀ = ²₅

The total number of candy canes at first and in the end remains unchanged. Make the total number of candy canes the same. LCM of 5 and 7 is 35.

Number of candy canes that Sean gave to Fabian
= 25 u - 21 u
= 4 u

4 u = 248

1 u = 248 ÷ 4 = 62

Number of candy canes that Fabian had in the end
= 14 u
= 14 x 62
= 868

Number of candy canes that Sean had in the end
= 21 u
= 21 x 62
= 1302

Answer(s): (a) 868; (b) 1302