Howard had 60% fewer caramel apples than Archie. After Archie gave 180 caramel apples to Howard, Howard had ²₃ as many caramel apples as Archie. How many caramel apples did each of them have in the end?

1. Archie
2. Howard

	Howard	Archie	Total
Before	2x5 = 10 u	5x5 = 25 u	7x5 = 35 u
Change	+ 180	- 180
After	2x7 = 14 u	3x7 =  21 u	5x7 = 35 u

Number of caramel apples that Howard had at first in percentage
= 100% - 60%
= 40%

40% = ⁴⁰₁₀₀ = ²₅

The total number of caramel apples at first and in the end remains unchanged. Make the total number of caramel apples the same. LCM of 5 and 7 is 35.

Number of caramel apples that Archie gave to Howard
= 25 u - 21 u
= 4 u

4 u = 180

1 u = 180 ÷ 4 = 45

Number of caramel apples that Howard had in the end
= 14 u
= 14 x 45
= 630

Number of caramel apples that Archie had in the end
= 21 u
= 21 x 45
= 945

Answer(s): (a) 630; (b) 945