Bobby had 60% fewer chocolate bars than Valen. After Valen gave 156 chocolate bars to Bobby, Bobby had
56 as many chocolate bars as Valen. How many chocolate bars did each of them have in the end?
- Valen
- Bobby
|
Bobby |
Valen |
Total |
Before |
2x11 = 22 u |
5x11 = 55 u |
7x11 = 77 u |
Change |
+ 156 |
- 156 |
|
After |
5x7 = 35 u |
6x7 = 42 u |
11x7 = 77 u |
Number of chocolate bars that Bobby had at first in percentage
= 100% - 60%
= 40%
40% =
40100 =
25 The total number of chocolate bars at first and in the end remains unchanged. Make the total number of chocolate bars the same. LCM of 11 and 7 is 77.
Number of chocolate bars that Valen gave to Bobby
= 55 u - 42 u
= 13 u
13 u = 156
1 u = 156 ÷ 13 = 12
Number of chocolate bars that Bobby had in the end
= 35 u
= 35 x 12
= 420
Number of chocolate bars that Valen had in the end
= 42 u
= 42 x 12
= 504
Answer(s): (a) 420; (b) 504