Perry had 80% fewer chocolate bars than Lee. After Lee gave 252 chocolate bars to Perry, Perry had ²₃ as many chocolate bars as Lee. How many chocolate bars did each of them have in the end?

1. Lee
2. Perry

	Perry	Lee	Total
Before	1x5 = 5 u	5x5 = 25 u	6x5 = 30 u
Change	+ 252	- 252
After	2x6 = 12 u	3x6 =  18 u	5x6 = 30 u

Number of chocolate bars that Perry had at first in percentage
= 100% - 80%
= 20%

20% = ²⁰₁₀₀ = ¹₅

The total number of chocolate bars at first and in the end remains unchanged. Make the total number of chocolate bars the same. LCM of 5 and 6 is 30.

Number of chocolate bars that Lee gave to Perry
= 25 u - 18 u
= 7 u

7 u = 252

1 u = 252 ÷ 7 = 36

Number of chocolate bars that Perry had in the end
= 12 u
= 12 x 36
= 432

Number of chocolate bars that Lee had in the end
= 18 u
= 18 x 36
= 648

Answer(s): (a) 432; (b) 648